Gmewangmo94 Gmewangmo94

03-09-2019
Physics

contestada

If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?

Respuesta :

Chenk13 Chenk13

03-09-2019

Answer:

v = -6m/s

Explanation:

[tex]x=4-12t+3t^2[/tex]

[tex]\frac{dx}{dt}=-12+6t[/tex]

For t = 1:

[tex]\frac{dx}{dt}=-6[/tex]

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