poolwaterisgross
poolwaterisgross poolwaterisgross
  • 01-02-2021
  • Mathematics
contestada

Find the inverse of the following function. g(x) = 1/x - 2

plz show work

A.) g^-1(x) = - 2/x-1

B.) g^-1(x) = 2/x-1

C.)g^-1(x) = 1/x+ 2

D.) g^-1(x) = 2/x+1

Respuesta :

GabbyMarie
GabbyMarie GabbyMarie
  • 02-02-2021

Answer: C. g^(-1) (x)= 1/(x+ 2)

Step-by-step explanation:

y=1/x-2

x=1/y-2

1/y-2=x

1/y=x+2

1=(x+2)y

1=xy+2y

xy+2y=1

(x+2)y=1

y=1/(x+2)

answer: g^(-1) (x)= 1/(x+ 2)

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